![]() InputStream input = getClass().getResourceAsStream(resource) įile = File.createTempFile("tempfile", ". In Maven, the classpath contains the exploded target/test-classes directory, so getResource(hello.txt).getFile() returns an absolute file path, suitable for. ![]() Second, well see how to read the content with BufferedReader, Scanner, StreamTokenizer, DataInputStream, SequenceInputStream, and FileChannel. First, well learn how to load a file from the classpath, a URL, or from a JAR file using standard Java classes. This method takes a File object as an argument and returns an Image object. URL res = getClass().getResource(resource) In this tutorial, well explore different ways to read from a File in Java. To get the path of an image file, you can use the ImageIO.read () method. When you really have to load a (non-image) file from a JAR archive, you might try this: File file = null For this you will need to create a resources folder in the projects root. I guess, this confusion is causing most of problems when loading a resource.Īlso, when you're loading an image it's easier to use getResourceAsStream(): BufferedImage image = ImageIO.read(getClass().getResourceAsStream("/com/myorg/foo.jpg")) Your application can load resources such as audio and image files at runtime. When loading a resource make sure you notice the difference between: getClass().getClassLoader().getResource("com/myorg/foo.jpg") //relative pathĪnd getClass().getResource("/com/myorg/foo.jpg")) //note the slash at the beginning
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